Groei

$3$ keer

$5$ miljoen

$64$ , nl $2^{6}$

$3,7 \cdot 10^{19}$ (ongeveer $65$ generaties)

Je telt voorouders dubbel.

$t$	0	1	2	3	4
$B (t)$	$1$	$2$	$4$	$8$	$16$

$B (t) = 2^{t}$

Ongeveer $5,6$

Rekenregels voor machten

$2^{8}$

$2^{2}$

$2^{15}$

$2^{2} \times 2^{3} = 2^{5}$

$2^{p} \times 2^{q} = 2^{p + q}$

$2^{p} : 2^{q} = 2^{p - q}$

${(2^{3})}^{4} = 2^{12}$

${(2^{p})}^{q} = 2^{p \cdot q}$

$2^{12}$	$2^{2}$	$2^{35}$
$2^{8}$	$2^{6}$	$2^{0}$

$10 000 = 10^{4}$

${(a \cdot b)}^{p} = a^{p} \cdot b^{p}$

Rekenregels toepassen

$x^{2}$

$y^{7}$

$1$

$p^{3} \cdot q^{2}$

$2$

$y^{5}$

$p^{15}$

$a \cdot b^{2}$

$2^{k + 5}$

$2^{k + 1}$

$2^{2 k}$

$2^{3 k}$

$2^{9 k}$

$2^{k + 2 m}$

$2^{5 - k}$

$2^{k - 1}$

$2^{2}$

$2^{3 k - 3}$

$2^{k}$

$2^{2 m - k}$

$3^{n} \cdot 9^{n} = 27^{n}$ ;
$4^{n} : 8^{n} = {(\frac{1}{2})}^{n}$ ;
$2^{n} + 2^{n} = 2^{n + 1}$